Matematika Sekolah Dasar a.(-14)×(225+87)÷(472-304)=b.1.023-152÷19+32×(-8)=c.5/8÷2/3×1/2+3/4=d.5×0,32+2 3/4÷1/2=pakai jalan​

rooseveltadamsulv – March 09, 2023

a.(-14)×(225+87)÷(472-304)=
b.1.023-152÷19+32×(-8)=
c.5/8÷2/3×1/2+3/4=
d.5×0,32+2 3/4÷1/2=
pakai jalan​

SOAL A.

[tex]( - 14) \times (225 + 87) \div (472 - 304)[/tex]

[tex]= ( - 14) \times 312 \div 168[/tex]

[tex]= ( - 4.368) \div 168 = ( - 26)[/tex]

SOAL B.

[tex]1.023 - 152 \div 19 + 32 \times ( - 8)[/tex]

[tex]= 1.023 - 8 + ( - 256)[/tex]

[tex]= 1.023 - 8 - 256 = 759[/tex]

SOAL C.

[tex]\frac{5}{8} \div \frac{2}{3} \times \frac{1}{2} + \frac{3}{4} [/tex] [tex]= \frac{5}{8} \times \frac{3}{2} \times \frac{1}{2} + \frac{3}{4} [/tex] [tex]= \frac{15}{32} + \frac{3}{4} [/tex]

[tex]= \frac{(15 \times 1)}{(32 \times 1)} + \frac{(3 \times 8)}{(4 \times 8)} [/tex] [tex]= \frac{15}{32} + \frac{24}{32} = \frac{39}{32} = 1 \frac{7}{32} [/tex]

SOAL D.

[tex]5 \times 0.32 + 2 \frac{3}{4} \div \frac{1}{2} [/tex] [tex]= 1.6 + \frac{11}{4} \times \frac{2}{1} [/tex] [tex]= \frac{16}{10} + \frac{22}{4} [/tex]

[tex]= \frac{(16 \times 2)}{(10 \times 2)} + \frac{(22 \times 5)}{(4 \times 5)} [/tex] [tex]= \frac{32}{20} + \frac{110}{20} = \frac{142}{20} = \frac{71}{10} = 7 \frac{1}{10} [/tex]

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